Thank you very much sir for your suggestions.

2. I will try to number the steps in future version.

1. The machine already shows the thing you are asking for.

You entered: राम + औ Go Back


arthavadadhAturapratyayaH prAtipadikam (1.2.45), kRttaddhitasamAsAzca (1.2.46), pratyayaH (3.1.1), parazca (3.1.2), GyAppradipadikAt (4.1.1), svaujasamauTCaSTAbhyAmbhisGebhyAmbhyasGasibhyAmbhyasGasosAmGyossup (4.1.2), vibhaktizca (1.4.104) and supaH (1.4.103) :

अर्थवदधातुरप्रत्ययः प्रातिपदिकम्‌ (१.२.४५), कृत्तद्धितसमासाश्च (१.२.४६), प्रत्ययः (३.१.१), परश्च (३.१.२), ङ्‍याप्प्रातिपदिकात्‌ (४.१.१), स्वौजसमौट्छष्टाभ्याम्भिस्ङेभ्याम्भ्यस्ङसिभ्याम्भ्यस्ङसोसाम्ङ्‍योस्सुप्‌ (४.१.२), विभक्तिश्च (१.४.१०४) तथा सुपः (१.४.१०३) :

1 - राम+औ


dvyekayordvivacanaikavacane (1.4.22) :

द्व्येकयोर्द्विवचनैकवचने (१.४.२२) :

1 - राम+औ


sarUpANAmekazeSa ekavibhaktau (1.2.64) :

सरूपाणामेकशेष एकविभक्तौ (१.२.६४) :

1 - राम+औ


By suDanapuMsakasya (1.1.43) :

सुडनपुंसकस्य (१.१.४३) :

1 - राम+औ


By nAdici (6.1.104) :

N.B. : This is exception to prathamayoH pUrvasavarNaH.

नादिचि (६.१.१०४) :

यह नियम प्रथमयोः पूर्वसवर्णः का अपवाद है ।

1 - राम+औ


By vRddhireci (6.1.88) :

वृद्धिरेचि (६.१.८८) :

1 - रामौ+


Final forms are :

आखिरी रूप हैं :

1 - रामौ





On Mon, Sep 8, 2014 at 9:59 AM, Malhar Arvind Kulkarni <malhar@iitb.ac.in> wrote:
Dear Dhaval,

Very good.


Since you say- "The machine gives step by step derivation of words as per
prakriyA mentioned in Siddhantakaumudi.", may I make one suggestion?

1. In the derivation of rAmau (1/2 and 2/2), can you mention the
pratiprasava of 6.1.88?

Also

2. Can you number the steps?

with regards.
Malhar Kulkarni.




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Dr. Dhaval Patel, I.A.S
District Development Officer, Rajkot
www.sanskritworld.in